4x+[16-2(3-5x)]=7(2x-5)

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Solution for 4x+[16-2(3-5x)]=7(2x-5) equation:


Simplifying
4x + [16 + -2(3 + -5x)] = 7(2x + -5)
4x + [16 + (3 * -2 + -5x * -2)] = 7(2x + -5)
4x + [16 + (-6 + 10x)] = 7(2x + -5)

Combine like terms: 16 + -6 = 10
4x + [10 + 10x] = 7(2x + -5)

Remove brackets around [10 + 10x]
4x + 10 + 10x = 7(2x + -5)

Reorder the terms:
10 + 4x + 10x = 7(2x + -5)

Combine like terms: 4x + 10x = 14x
10 + 14x = 7(2x + -5)

Reorder the terms:
10 + 14x = 7(-5 + 2x)
10 + 14x = (-5 * 7 + 2x * 7)
10 + 14x = (-35 + 14x)

Add '-14x' to each side of the equation.
10 + 14x + -14x = -35 + 14x + -14x

Combine like terms: 14x + -14x = 0
10 + 0 = -35 + 14x + -14x
10 = -35 + 14x + -14x

Combine like terms: 14x + -14x = 0
10 = -35 + 0
10 = -35

Solving
10 = -35

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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